(x+4)(x+2)=x-(1-x2)

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Solution for (x+4)(x+2)=x-(1-x2) equation:



(x+4)(x+2)=x-(1-x2)
We move all terms to the left:
(x+4)(x+2)-(x-(1-x2))=0
We add all the numbers together, and all the variables
-(x-(-1x^2+1))+(x+4)(x+2)=0
We multiply parentheses ..
-(x-(-1x^2+1))+(+x^2+2x+4x+8)=0
We calculate terms in parentheses: -(x-(-1x^2+1)), so:
x-(-1x^2+1)
determiningTheFunctionDomain -(-1x^2+1)+x
We get rid of parentheses
1x^2+x-1
We add all the numbers together, and all the variables
x^2+x-1
Back to the equation:
-(x^2+x-1)
We get rid of parentheses
x^2-x^2+2x+4x-x+8+1=0
We add all the numbers together, and all the variables
5x+9=0
We move all terms containing x to the left, all other terms to the right
5x=-9
x=-9/5
x=-1+4/5

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