(x+4)(x+3)=(x+1)(x+5)

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Solution for (x+4)(x+3)=(x+1)(x+5) equation: 



(x+4)(x+3)=(x+1)(x+5)

We move all terms to the left:

(x+4)(x+3)-((x+1)(x+5))=0

We multiply parentheses ..

(+x^2+3x+4x+12)-((x+1)(x+5))=0



We calculate terms in parentheses: -((x+1)(x+5)), so:

(x+1)(x+5)

We multiply parentheses ..

(+x^2+5x+x+5)

We get rid of parentheses

x^2+5x+x+5

We add all the numbers together, and all the variables

x^2+6x+5

Back to the equation:

-(x^2+6x+5)



We get rid of parentheses

x^2-x^2+3x+4x-6x+12-5=0

We add all the numbers together, and all the variables

x+7=0

We move all terms containing x to the left, all other terms to the right

x=-7

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