(x+4)(x+3)=(x+5)(x+2)

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Solution for (x+4)(x+3)=(x+5)(x+2) equation: 



(x+4)(x+3)=(x+5)(x+2)

We move all terms to the left:

(x+4)(x+3)-((x+5)(x+2))=0

We multiply parentheses ..

(+x^2+3x+4x+12)-((x+5)(x+2))=0



We calculate terms in parentheses: -((x+5)(x+2)), so:

(x+5)(x+2)

We multiply parentheses ..

(+x^2+2x+5x+10)

We get rid of parentheses

x^2+2x+5x+10

We add all the numbers together, and all the variables

x^2+7x+10

Back to the equation:

-(x^2+7x+10)



We get rid of parentheses

x^2-x^2+3x+4x-7x+12-10=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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