(x+4)(x+4)-(x-6)(x-6)=10x

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Solution for (x+4)(x+4)-(x-6)(x-6)=10x equation: 



(x+4)(x+4)-(x-6)(x-6)=10x

We move all terms to the left:

(x+4)(x+4)-(x-6)(x-6)-(10x)=0

We add all the numbers together, and all the variables

-10x+(x+4)(x+4)-(x-6)(x-6)=0

We multiply parentheses ..

(+x^2+4x+4x+16)-10x-(x-6)(x-6)=0

We get rid of parentheses

x^2+4x+4x-10x-(x-6)(x-6)+16=0

We multiply parentheses ..

x^2-(+x^2-6x-6x+36)+4x+4x-10x+16=0

We add all the numbers together, and all the variables

x^2-(+x^2-6x-6x+36)-2x+16=0

We get rid of parentheses

x^2-x^2+6x+6x-2x-36+16=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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