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(x+4)(x+4)=2x(2x)+16x+23
We move all terms to the left:
(x+4)(x+4)-(2x(2x)+16x+23)=0
We add all the numbers together, and all the variables
(x+4)(x+4)-(16x+2x2x+23)=0
We get rid of parentheses
(x+4)(x+4)-16x-2x2x-23=0
We multiply parentheses ..
(+x^2+4x+4x+16)-16x-2x2x-23=0
We get rid of parentheses
x^2+4x+4x-16x-2x2x+16-23=0
We add all the numbers together, and all the variables
x^2-8x-2x2x-7=0
We move all terms containing x to the left, all other terms to the right
x^2-8x-2x2x=7
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