(x+4)(x+4)=x(x+12)

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Solution for (x+4)(x+4)=x(x+12) equation: 



(x+4)(x+4)=x(x+12)

We move all terms to the left:

(x+4)(x+4)-(x(x+12))=0

We multiply parentheses ..

(+x^2+4x+4x+16)-(x(x+12))=0



We calculate terms in parentheses: -(x(x+12)), so:

x(x+12)

We multiply parentheses

x^2+12x

Back to the equation:

-(x^2+12x)



We get rid of parentheses

x^2-x^2+4x+4x-12x+16=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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