(x+4)(x+6)=(x+1)(x+12)

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Solution for (x+4)(x+6)=(x+1)(x+12) equation: 



(x+4)(x+6)=(x+1)(x+12)

We move all terms to the left:

(x+4)(x+6)-((x+1)(x+12))=0

We multiply parentheses ..

(+x^2+6x+4x+24)-((x+1)(x+12))=0



We calculate terms in parentheses: -((x+1)(x+12)), so:

(x+1)(x+12)

We multiply parentheses ..

(+x^2+12x+x+12)

We get rid of parentheses

x^2+12x+x+12

We add all the numbers together, and all the variables

x^2+13x+12

Back to the equation:

-(x^2+13x+12)



We get rid of parentheses

x^2-x^2+6x+4x-13x+24-12=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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