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(x+4)(x+8)=184
We move all terms to the left:
(x+4)(x+8)-(184)=0
We multiply parentheses ..
(+x^2+8x+4x+32)-184=0
We get rid of parentheses
x^2+8x+4x+32-184=0
We add all the numbers together, and all the variables
x^2+12x-152=0
a = 1; b = 12; c = -152;
Δ = b2-4ac
Δ = 122-4·1·(-152)
Δ = 752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{752}=\sqrt{16*47}=\sqrt{16}*\sqrt{47}=4\sqrt{47}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{47}}{2*1}=\frac{-12-4\sqrt{47}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{47}}{2*1}=\frac{-12+4\sqrt{47}}{2} $
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