(x+4)(x-)=x2-6x-40

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Solution for (x+4)(x-)=x2-6x-40 equation: 



(x+4)(x-)=x2-6x-40

We move all terms to the left:

(x+4)(x-)-(x2-6x-40)=0

We add all the numbers together, and all the variables

-(+x^2-6x-40)+(x+4)(+x)=0

We get rid of parentheses

-x^2+6x+(x+4)(+x)+40=0

We multiply parentheses ..

-x^2+(+x^2+4x)+6x+40=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+4x)+6x+40=0

We get rid of parentheses

-1x^2+x^2+4x+6x+40=0

We add all the numbers together, and all the variables

10x+40=0

We move all terms containing x to the left, all other terms to the right

10x=-40

x=-40/10

x=-4

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