(x+4)(x-12)=0

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Solution for (x+4)(x-12)=0 equation:


Simplifying
(x + 4)(x + -12) = 0

Reorder the terms:
(4 + x)(x + -12) = 0

Reorder the terms:
(4 + x)(-12 + x) = 0

Multiply (4 + x) * (-12 + x)
(4(-12 + x) + x(-12 + x)) = 0
((-12 * 4 + x * 4) + x(-12 + x)) = 0
((-48 + 4x) + x(-12 + x)) = 0
(-48 + 4x + (-12 * x + x * x)) = 0
(-48 + 4x + (-12x + x2)) = 0

Combine like terms: 4x + -12x = -8x
(-48 + -8x + x2) = 0

Solving
-48 + -8x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-4 + -1x)(12 + -1x) = 0

Subproblem 1

Set the factor '(-4 + -1x)' equal to zero and attempt to solve: Simplifying -4 + -1x = 0 Solving -4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1x = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1x = 0 + 4 -1x = 0 + 4 Combine like terms: 0 + 4 = 4 -1x = 4 Divide each side by '-1'. x = -4 Simplifying x = -4

Subproblem 2

Set the factor '(12 + -1x)' equal to zero and attempt to solve: Simplifying 12 + -1x = 0 Solving 12 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1x = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1x = 0 + -12 -1x = 0 + -12 Combine like terms: 0 + -12 = -12 -1x = -12 Divide each side by '-1'. x = 12 Simplifying x = 12

Solution

x = {-4, 12}

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