(x+4)(x-2)=x2+20

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Solution for (x+4)(x-2)=x2+20 equation: 



(x+4)(x-2)=x2+20

We move all terms to the left:

(x+4)(x-2)-(x2+20)=0

We add all the numbers together, and all the variables

-(+x^2+20)+(x+4)(x-2)=0

We get rid of parentheses

-x^2+(x+4)(x-2)-20=0

We multiply parentheses ..

-x^2+(+x^2-2x+4x-8)-20=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-2x+4x-8)-20=0

We get rid of parentheses

-1x^2+x^2-2x+4x-8-20=0

We add all the numbers together, and all the variables

2x-28=0

We move all terms containing x to the left, all other terms to the right

2x=28

x=28/2

x=14

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