(x+4)(x-3)=(x-2)(x+1

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Solution for (x+4)(x-3)=(x-2)(x+1 equation: 



(x+4)(x-3)=(x-2)(x+1

We move all terms to the left:

(x+4)(x-3)-((x-2)(x+1)=0

We multiply parentheses ..

(+x^2-3x+4x-12)-((x-2)(x+1)=0



We calculate terms in parentheses: -((x-2)(x+1), so:

(x-2)(x+1



We get rid of parentheses

x^2-3x+4x-((x-2)(x+1)-12=0

We multiply parentheses ..

x^2-((+x^2+x-2x-2)-12-3x+4x=0

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