(x+4)(x-4)(2x-1)=0

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Solution for (x+4)(x-4)(2x-1)=0 equation: 


Simplifying
(x + 4)(x + -4)(2x + -1) = 0

Reorder the terms:
(4 + x)(x + -4)(2x + -1) = 0

Reorder the terms:
(4 + x)(-4 + x)(2x + -1) = 0

Reorder the terms:
(4 + x)(-4 + x)(-1 + 2x) = 0

Multiply (4 + x) * (-4 + x)
(4(-4 + x) + x(-4 + x))(-1 + 2x) = 0
((-4 * 4 + x * 4) + x(-4 + x))(-1 + 2x) = 0
((-16 + 4x) + x(-4 + x))(-1 + 2x) = 0
(-16 + 4x + (-4 * x + x * x))(-1 + 2x) = 0
(-16 + 4x + (-4x + x2))(-1 + 2x) = 0

Combine like terms: 4x + -4x = 0
(-16 + 0 + x2)(-1 + 2x) = 0
(-16 + x2)(-1 + 2x) = 0

Multiply (-16 + x2) * (-1 + 2x)
(-16(-1 + 2x) + x2(-1 + 2x)) = 0
((-1 * -16 + 2x * -16) + x2(-1 + 2x)) = 0
((16 + -32x) + x2(-1 + 2x)) = 0
(16 + -32x + (-1 * x2 + 2x * x2)) = 0
(16 + -32x + (-1x2 + 2x3)) = 0
(16 + -32x + -1x2 + 2x3) = 0

Solving
16 + -32x + -1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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