(x+4)(x-7-5)(x+7-5)=0

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Solution for (x+4)(x-7-5)(x+7-5)=0 equation: 



(x+4)(x-7-5)(x+7-5)=0

We add all the numbers together, and all the variables

(x+4)(x-12)(x+2)=0

We multiply parentheses ..

(+x^2-12x+4x-48)(x+2)=0

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