(x+4)(x-9)=(x)(x-12)

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Solution for (x+4)(x-9)=(x)(x-12) equation: 



(x+4)(x-9)=(x)(x-12)

We move all terms to the left:

(x+4)(x-9)-((x)(x-12))=0

We multiply parentheses ..

(+x^2-9x+4x-36)-(x(x-12))=0



We calculate terms in parentheses: -(x(x-12)), so:

x(x-12)

We multiply parentheses

x^2-12x

Back to the equation:

-(x^2-12x)



We get rid of parentheses

x^2-x^2-9x+4x+12x-36=0

We add all the numbers together, and all the variables

7x-36=0

We move all terms containing x to the left, all other terms to the right

7x=36

x=36/7

x=5+1/7

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