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(x+4)(3-10x)=0
We add all the numbers together, and all the variables
(x+4)(-10x+3)=0
We multiply parentheses ..
(-10x^2+3x-40x+12)=0
We get rid of parentheses
-10x^2+3x-40x+12=0
We add all the numbers together, and all the variables
-10x^2-37x+12=0
a = -10; b = -37; c = +12;
Δ = b2-4ac
Δ = -372-4·(-10)·12
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-43}{2*-10}=\frac{-6}{-20} =3/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+43}{2*-10}=\frac{80}{-20} =-4 $
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