(x+4)+(2x+1)+(3x-2)=

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Solution for (x+4)+(2x+1)+(3x-2)= equation:


Simplifying
(x + 4) + (2x + 1) + (3x + -2) = 0

Reorder the terms:
(4 + x) + (2x + 1) + (3x + -2) = 0

Remove parenthesis around (4 + x)
4 + x + (2x + 1) + (3x + -2) = 0

Reorder the terms:
4 + x + (1 + 2x) + (3x + -2) = 0

Remove parenthesis around (1 + 2x)
4 + x + 1 + 2x + (3x + -2) = 0

Reorder the terms:
4 + x + 1 + 2x + (-2 + 3x) = 0

Remove parenthesis around (-2 + 3x)
4 + x + 1 + 2x + -2 + 3x = 0

Reorder the terms:
4 + 1 + -2 + x + 2x + 3x = 0

Combine like terms: 4 + 1 = 5
5 + -2 + x + 2x + 3x = 0

Combine like terms: 5 + -2 = 3
3 + x + 2x + 3x = 0

Combine like terms: x + 2x = 3x
3 + 3x + 3x = 0

Combine like terms: 3x + 3x = 6x
3 + 6x = 0

Solving
3 + 6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 6x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 6x = 0 + -3
6x = 0 + -3

Combine like terms: 0 + -3 = -3
6x = -3

Divide each side by '6'.
x = -0.5

Simplifying
x = -0.5

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