(x+4)+(5z+1)=-2(z+1)

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Solution for (x+4)+(5z+1)=-2(z+1) equation:


Simplifying
(x + 4) + (5z + 1) = -2(z + 1)

Reorder the terms:
(4 + x) + (5z + 1) = -2(z + 1)

Remove parenthesis around (4 + x)
4 + x + (5z + 1) = -2(z + 1)

Reorder the terms:
4 + x + (1 + 5z) = -2(z + 1)

Remove parenthesis around (1 + 5z)
4 + x + 1 + 5z = -2(z + 1)

Reorder the terms:
4 + 1 + x + 5z = -2(z + 1)

Combine like terms: 4 + 1 = 5
5 + x + 5z = -2(z + 1)

Reorder the terms:
5 + x + 5z = -2(1 + z)
5 + x + 5z = (1 * -2 + z * -2)
5 + x + 5z = (-2 + -2z)

Solving
5 + x + 5z = -2 + -2z

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + x + -5 + 5z = -2 + -5 + -2z

Reorder the terms:
5 + -5 + x + 5z = -2 + -5 + -2z

Combine like terms: 5 + -5 = 0
0 + x + 5z = -2 + -5 + -2z
x + 5z = -2 + -5 + -2z

Combine like terms: -2 + -5 = -7
x + 5z = -7 + -2z

Add '-5z' to each side of the equation.
x + 5z + -5z = -7 + -2z + -5z

Combine like terms: 5z + -5z = 0
x + 0 = -7 + -2z + -5z
x = -7 + -2z + -5z

Combine like terms: -2z + -5z = -7z
x = -7 + -7z

Simplifying
x = -7 + -7z

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