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(x+4)+(x+2)+(x+5)=2(x+3)+2(x+1)
We move all terms to the left:
(x+4)+(x+2)+(x+5)-(2(x+3)+2(x+1))=0
We get rid of parentheses
x+x+x-(2(x+3)+2(x+1))+4+2+5=0
We calculate terms in parentheses: -(2(x+3)+2(x+1)), so:We add all the numbers together, and all the variables
2(x+3)+2(x+1)
We multiply parentheses
2x+2x+6+2
We add all the numbers together, and all the variables
4x+8
Back to the equation:
-(4x+8)
3x-(4x+8)+11=0
We get rid of parentheses
3x-4x-8+11=0
We add all the numbers together, and all the variables
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3
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