(x+4)/(2x+1)+(x-3)/(4x-9)=1

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Solution for (x+4)/(2x+1)+(x-3)/(4x-9)=1 equation:



(x+4)/(2x+1)+(x-3)/(4x-9)=1
We move all terms to the left:
(x+4)/(2x+1)+(x-3)/(4x-9)-(1)=0
Domain of the equation: (2x+1)!=0
We move all terms containing x to the left, all other terms to the right
2x!=-1
x!=-1/2
x!=-1/2
x∈R
Domain of the equation: (4x-9)!=0
We move all terms containing x to the left, all other terms to the right
4x!=9
x!=9/4
x!=2+1/4
x∈R
We calculate fractions
((x+4)*(4x-9))/((2x+1)*(4x-9))+((x-3)*(2x+1))/((2x+1)*(4x-9))-1=0
We calculate terms in parentheses: +((x+4)*(4x-9))/((2x+1)*(4x-9)), so:
(x+4)*(4x-9))/((2x+1)*(4x-9)
We multiply all the terms by the denominator
(x+4)*(4x-9))
Back to the equation:
+((x+4)*(4x-9)))
We calculate terms in parentheses: +((x-3)*(2x+1))/((2x+1)*(4x-9)), so:
(x-3)*(2x+1))/((2x+1)*(4x-9)
We multiply all the terms by the denominator
(x-3)*(2x+1))
Back to the equation:
+((x-3)*(2x+1)))

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