(x+4)/(3x+12)=0

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Solution for (x+4)/(3x+12)=0 equation: 


D( x )

3*x+12 = 0

3*x+12 = 0

3*x+12 = 0

3*x+12 = 0 // - 12

3*x = -12 // : 3

x = -12/3

x = -4

x in (-oo:-4) U (-4:+oo)

(x+4)/(3*x+12) = 0

x+4 = 0 // - 4

x = -4

x in { -4} 

x belongs to the empty set

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