(x+4)/(3x-2)=5

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Solution for (x+4)/(3x-2)=5 equation: 



(x+4)/(3x-2)=5

We move all terms to the left:

(x+4)/(3x-2)-(5)=0



Domain of the equation: (3x-2)!=0

We move all terms containing x to the left, all other terms to the right

3x!=2

x!=2/3

x!=2/3

x∈R



We multiply all the terms by the denominator


(x+4)-5*(3x-2)=0

We multiply parentheses

(x+4)-15x+10=0

We get rid of parentheses

x-15x+4+10=0

We add all the numbers together, and all the variables

-14x+14=0

We move all terms containing x to the left, all other terms to the right

-14x=-14

x=-14/-14

x=1

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