(x+4)/2=4-(x+2)/3

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Solution for (x+4)/2=4-(x+2)/3 equation: 



(x+4)/2=4-(x+2)/3

We move all terms to the left:

(x+4)/2-(4-(x+2)/3)=0

We calculate fractions


x/()+(-(4-(x+2)*2)/()=0



We calculate terms in parentheses: +(-(4-(x+2)*2)/(), so:

-(4-(x+2)*2)/(

We multiply all the terms by the denominator


-(4-(x+2)*2)



We calculate terms in parentheses: -(4-(x+2)*2), so:

4-(x+2)*2

determiningTheFunctionDomain
-(x+2)*2+4

We multiply parentheses

-2x-4+4

We add all the numbers together, and all the variables

-2x

Back to the equation:

-(-2x)



We get rid of parentheses

2x

Back to the equation:

+(2x)



We add all the numbers together, and all the variables

2x+x/()=0

We multiply all the terms by the denominator


2x*()+x=0

We add all the numbers together, and all the variables

x+2x*()=0

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