(x+4)/4=(2x+1)/6

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Solution for (x+4)/4=(2x+1)/6 equation:



(x+4)/4=(2x+1)/6
We move all terms to the left:
(x+4)/4-((2x+1)/6)=0
We calculate fractions
x/()+(-((2x+1)*4)/()=0
We calculate terms in parentheses: +(-((2x+1)*4)/(), so:
-((2x+1)*4)/(
We multiply all the terms by the denominator
-((2x+1)*4)
We calculate terms in parentheses: -((2x+1)*4), so:
(2x+1)*4
We multiply parentheses
8x+4
Back to the equation:
-(8x+4)
We get rid of parentheses
-8x-4
Back to the equation:
+(-8x-4)
We get rid of parentheses
x/()-8x-4=0
We multiply all the terms by the denominator
x-8x*()-4*()=0
We add all the numbers together, and all the variables
x-8x*()=0

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