(x+4)/6=(x+1)/3

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Solution for (x+4)/6=(x+1)/3 equation: 



(x+4)/6=(x+1)/3

We move all terms to the left:

(x+4)/6-((x+1)/3)=0

We calculate fractions


x/()+(-((x+1)*6)/()=0



We calculate terms in parentheses: +(-((x+1)*6)/(), so:

-((x+1)*6)/(

We multiply all the terms by the denominator


-((x+1)*6)



We calculate terms in parentheses: -((x+1)*6), so:

(x+1)*6

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

-6x-6

Back to the equation:

+(-6x-6)



We get rid of parentheses

x/()-6x-6=0

We multiply all the terms by the denominator


x-6x*()-6*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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