(x+4)2+(y+4)2=32

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Solution for (x+4)2+(y+4)2=32 equation: 


Simplifying
(x + 4) * 2 + (y + 4) * 2 = 32

Reorder the terms:
(4 + x) * 2 + (y + 4) * 2 = 32

Reorder the terms for easier multiplication:
2(4 + x) + (y + 4) * 2 = 32
(4 * 2 + x * 2) + (y + 4) * 2 = 32
(8 + 2x) + (y + 4) * 2 = 32

Reorder the terms:
8 + 2x + (4 + y) * 2 = 32

Reorder the terms for easier multiplication:
8 + 2x + 2(4 + y) = 32
8 + 2x + (4 * 2 + y * 2) = 32
8 + 2x + (8 + 2y) = 32

Reorder the terms:
8 + 8 + 2x + 2y = 32

Combine like terms: 8 + 8 = 16
16 + 2x + 2y = 32

Solving
16 + 2x + 2y = 32

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + 2x + -16 + 2y = 32 + -16

Reorder the terms:
16 + -16 + 2x + 2y = 32 + -16

Combine like terms: 16 + -16 = 0
0 + 2x + 2y = 32 + -16
2x + 2y = 32 + -16

Combine like terms: 32 + -16 = 16
2x + 2y = 16

Add '-2y' to each side of the equation.
2x + 2y + -2y = 16 + -2y

Combine like terms: 2y + -2y = 0
2x + 0 = 16 + -2y
2x = 16 + -2y

Divide each side by '2'.
x = 8 + -1y

Simplifying
x = 8 + -1y

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