(x+4)2=4x+20+4x

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Solution for (x+4)2=4x+20+4x equation: 



(x+4)2=4x+20+4x

We move all terms to the left:

(x+4)2-(4x+20+4x)=0

We add all the numbers together, and all the variables

(x+4)2-(8x+20)=0

We multiply parentheses

2x-(8x+20)+8=0

We get rid of parentheses

2x-8x-20+8=0

We add all the numbers together, and all the variables

-6x-12=0

We move all terms containing x to the left, all other terms to the right

-6x=12

x=12/-6

x=-2

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