(x+4)2=x2+16

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Solution for (x+4)2=x2+16 equation: 



(x+4)2=x2+16

We move all terms to the left:

(x+4)2-(x2+16)=0

We add all the numbers together, and all the variables

-(+x^2+16)+(x+4)2=0

We multiply parentheses

-(+x^2+16)+2x+8=0

We get rid of parentheses

-x^2+2x-16+8=0

We add all the numbers together, and all the variables

-1x^2+2x-8=0

a = -1; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·(-1)·(-8)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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