(x+4)=x+(x+2)+(x+4)-2

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Solution for (x+4)=x+(x+2)+(x+4)-2 equation: 



(x+4)=x+(x+2)+(x+4)-2

We move all terms to the left:

(x+4)-(x+(x+2)+(x+4)-2)=0

We get rid of parentheses

x-(x+(x+2)+(x+4)-2)+4=0



We calculate terms in parentheses: -(x+(x+2)+(x+4)-2), so:

x+(x+2)+(x+4)-2

We get rid of parentheses

x+x+x+2+4-2

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We get rid of parentheses

x-3x-4+4=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0

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