(x+4/9x)+1+(x+9/x)

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Solution for (x+4/9x)+1+(x+9/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+(4/9)*x+x+9/x+1 = 0

22/9*x^1+9*x^-1+1*x^0 = 0

(22/9*x^2+1*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(22/9*x^2+1*x^1+9*x^0) = 0

x^1

(22/9)*x^2+x+9 = 0

(22/9)*x^2+x+9 = 0

DELTA = 1^2-(4*9*(22/9))

DELTA = -87

DELTA < 0

x in { } 

x belongs to the empty set

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