(x+4/x-3)-(2x+5/2x)=0

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Solution for (x+4/x-3)-(2x+5/2x)=0 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(2*x)-((5/2)*x)+4/x-3 = 0

x-2*x+(-5/2)*x+4/x-3 = 0

4*x^-1-7/2*x^1-3*x^0 = 0

(4*x^0-7/2*x^2-3*x^1)/(x^1) = 0 // * x^2

x^1*(4*x^0-7/2*x^2-3*x^1) = 0

x^1

(-7/2)*x^2-3*x+4 = 0

(-7/2)*x^2-3*x+4 = 0

DELTA = (-3)^2-(4*4*(-7/2))

DELTA = 65

DELTA > 0

x = (65^(1/2)+3)/(2*(-7/2)) or x = (3-65^(1/2))/(2*(-7/2))

x = (65^(1/2)+3)/(-7) or x = (3-65^(1/2))/(-7)

x in { (65^(1/2)+3)/(-7), (3-65^(1/2))/(-7)}

x in { (65^(1/2)+3)/(-7), (3-65^(1/2))/(-7) }

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