(x+40)+(6x+20)+(4x-5)=180

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Solution for (x+40)+(6x+20)+(4x-5)=180 equation: 



(x+40)+(6x+20)+(4x-5)=180

We move all terms to the left:

(x+40)+(6x+20)+(4x-5)-(180)=0

We get rid of parentheses

x+6x+4x+40+20-5-180=0

We add all the numbers together, and all the variables

11x-125=0

We move all terms containing x to the left, all other terms to the right

11x=125

x=125/11

x=11+4/11

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