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(x+44)(7x-248)=180
We move all terms to the left:
(x+44)(7x-248)-(180)=0
We multiply parentheses ..
(+7x^2-248x+308x-10912)-180=0
We get rid of parentheses
7x^2-248x+308x-10912-180=0
We add all the numbers together, and all the variables
7x^2+60x-11092=0
a = 7; b = 60; c = -11092;
Δ = b2-4ac
Δ = 602-4·7·(-11092)
Δ = 314176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{314176}=\sqrt{64*4909}=\sqrt{64}*\sqrt{4909}=8\sqrt{4909}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-8\sqrt{4909}}{2*7}=\frac{-60-8\sqrt{4909}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+8\sqrt{4909}}{2*7}=\frac{-60+8\sqrt{4909}}{14} $
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