(x+48)(8x-7)=0

Solution for (x+48)(8x-7)=0 equation:

(x+48)(8x-7)=0

We multiply parentheses ..

(+8x^2-7x+384x-336)=0

We get rid of parentheses

8x^2-7x+384x-336=0

We add all the numbers together, and all the variables

8x^2+377x-336=0

a = 8; b = 377; c = -336;
Δ = b2-4ac
Δ = 3772-4·8·(-336)
Δ = 152881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{152881}=391$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(377)-391}{2*8}=\frac{-768}{16}
=-48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(377)+391}{2*8}=\frac{14}{16}
=7/8
$