(x+4i)(x-4i)=0

Solution for (x+4i)(x-4i)=0 equation:

Simplifying
(x + 4i)(x + -4i) = 0

Reorder the terms:
(4i + x)(x + -4i) = 0

Reorder the terms:
(4i + x)(-4i + x) = 0

Multiply (4i + x) * (-4i + x)
(4i * (-4i + x) + x(-4i + x)) = 0
((-4i * 4i + x * 4i) + x(-4i + x)) = 0

Reorder the terms:
((4ix + -16i2) + x(-4i + x)) = 0
((4ix + -16i2) + x(-4i + x)) = 0
(4ix + -16i2 + (-4i * x + x * x)) = 0
(4ix + -16i2 + (-4ix + x2)) = 0

Reorder the terms:
(4ix + -4ix + -16i2 + x2) = 0

Combine like terms: 4ix + -4ix = 0
(0 + -16i2 + x2) = 0
(-16i2 + x2) = 0

Solving
-16i2 + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
-16i2 + x2 + -1x2 = 0 + -1x2

Combine like terms: x2 + -1x2 = 0
-16i2 + 0 = 0 + -1x2
-16i2 = 0 + -1x2
Remove the zero:
-16i2 = -1x2

Divide each side by '-16'.
i2 = 0.0625x2

Simplifying
i2 = 0.0625x2

Take the square root of each side:
i = {-0.25x, 0.25x}