(x+5)(2x+7)-(x+5)(x-3)=(x+5)(x+10)

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Solution for (x+5)(2x+7)-(x+5)(x-3)=(x+5)(x+10) equation:



(x+5)(2x+7)-(x+5)(x-3)=(x+5)(x+10)
We move all terms to the left:
(x+5)(2x+7)-(x+5)(x-3)-((x+5)(x+10))=0
We multiply parentheses ..
(+2x^2+7x+10x+35)-(x+5)(x-3)-((x+5)(x+10))=0
We calculate terms in parentheses: -((x+5)(x+10)), so:
(x+5)(x+10)
We multiply parentheses ..
(+x^2+10x+5x+50)
We get rid of parentheses
x^2+10x+5x+50
We add all the numbers together, and all the variables
x^2+15x+50
Back to the equation:
-(x^2+15x+50)
We get rid of parentheses
2x^2-x^2+7x+10x-(x+5)(x-3)-15x+35-50=0
We multiply parentheses ..
2x^2-x^2-(+x^2-3x+5x-15)+7x+10x-15x+35-50=0
We add all the numbers together, and all the variables
x^2-(+x^2-3x+5x-15)+2x-15=0
We get rid of parentheses
x^2-x^2+3x-5x+2x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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