(x+5)(2x-10)=0

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Solution for (x+5)(2x-10)=0 equation:


Simplifying
(x + 5)(2x + -10) = 0

Reorder the terms:
(5 + x)(2x + -10) = 0

Reorder the terms:
(5 + x)(-10 + 2x) = 0

Multiply (5 + x) * (-10 + 2x)
(5(-10 + 2x) + x(-10 + 2x)) = 0
((-10 * 5 + 2x * 5) + x(-10 + 2x)) = 0
((-50 + 10x) + x(-10 + 2x)) = 0
(-50 + 10x + (-10 * x + 2x * x)) = 0
(-50 + 10x + (-10x + 2x2)) = 0

Combine like terms: 10x + -10x = 0
(-50 + 0 + 2x2) = 0
(-50 + 2x2) = 0

Solving
-50 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.
-50 + 50 + 2x2 = 0 + 50

Combine like terms: -50 + 50 = 0
0 + 2x2 = 0 + 50
2x2 = 0 + 50

Combine like terms: 0 + 50 = 50
2x2 = 50

Divide each side by '2'.
x2 = 25

Simplifying
x2 = 25

Take the square root of each side:
x = {-5, 5}

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