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(x+5)(4+x)=(x-4)(x-2)
We move all terms to the left:
(x+5)(4+x)-((x-4)(x-2))=0
We add all the numbers together, and all the variables
(x+5)(x+4)-((x-4)(x-2))=0
We multiply parentheses ..
(+x^2+4x+5x+20)-((x-4)(x-2))=0
We calculate terms in parentheses: -((x-4)(x-2)), so:We get rid of parentheses
(x-4)(x-2)
We multiply parentheses ..
(+x^2-2x-4x+8)
We get rid of parentheses
x^2-2x-4x+8
We add all the numbers together, and all the variables
x^2-6x+8
Back to the equation:
-(x^2-6x+8)
x^2-x^2+4x+5x+6x+20-8=0
We add all the numbers together, and all the variables
15x+12=0
We move all terms containing x to the left, all other terms to the right
15x=-12
x=-12/15
x=-4/5
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