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(x+5)(x+10)-1050=0
We multiply parentheses ..
(+x^2+10x+5x+50)-1050=0
We get rid of parentheses
x^2+10x+5x+50-1050=0
We add all the numbers together, and all the variables
x^2+15x-1000=0
a = 1; b = 15; c = -1000;
Δ = b2-4ac
Δ = 152-4·1·(-1000)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-65}{2*1}=\frac{-80}{2} =-40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+65}{2*1}=\frac{50}{2} =25 $
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