(x+5)(x+2)-3(4x-3)=(x-5)

Solution for (x+5)(x+2)-3(4x-3)=(x-5) equation:

(x+5)(x+2)-3(4x-3)=(x-5)

We move all terms to the left:

(x+5)(x+2)-3(4x-3)-((x-5))=0

We multiply parentheses

(x+5)(x+2)-12x-((x-5))+9=0

We multiply parentheses ..

(+x^2+2x+5x+10)-12x-((x-5))+9=0


We calculate terms in parentheses: -((x-5)), so:

(x-5)

We get rid of parentheses

x-5

Back to the equation:

-(x-5)


We get rid of parentheses

x^2+2x+5x-12x-x+10+5+9=0

We add all the numbers together, and all the variables

x^2-6x+24=0

a = 1; b = -6; c = +24;
Δ = b2-4ac
Δ = -62-4·1·24
Δ = -60
Delta is less than zero, so there is no solution for the equation