(x+5)(x+2)-3(4x-3)=(x-5)(x-5)

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Solution for (x+5)(x+2)-3(4x-3)=(x-5)(x-5) equation: 



(x+5)(x+2)-3(4x-3)=(x-5)(x-5)

We move all terms to the left:

(x+5)(x+2)-3(4x-3)-((x-5)(x-5))=0

We multiply parentheses

(x+5)(x+2)-12x-((x-5)(x-5))+9=0

We multiply parentheses ..

(+x^2+2x+5x+10)-12x-((x-5)(x-5))+9=0



We calculate terms in parentheses: -((x-5)(x-5)), so:

(x-5)(x-5)

We multiply parentheses ..

(+x^2-5x-5x+25)

We get rid of parentheses

x^2-5x-5x+25

We add all the numbers together, and all the variables

x^2-10x+25

Back to the equation:

-(x^2-10x+25)



We get rid of parentheses

x^2-x^2+2x+5x-12x+10x+10-25+9=0

We add all the numbers together, and all the variables

5x-6=0

We move all terms containing x to the left, all other terms to the right

5x=6

x=6/5

x=1+1/5

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