(x+5)(x+2)=(x-3)(x+1)

Solution for (x+5)(x+2)=(x-3)(x+1) equation:

(x+5)(x+2)=(x-3)(x+1)

We move all terms to the left:

(x+5)(x+2)-((x-3)(x+1))=0

We multiply parentheses ..

(+x^2+2x+5x+10)-((x-3)(x+1))=0


We calculate terms in parentheses: -((x-3)(x+1)), so:

(x-3)(x+1)

We multiply parentheses ..

(+x^2+x-3x-3)

We get rid of parentheses

x^2+x-3x-3

We add all the numbers together, and all the variables

x^2-2x-3

Back to the equation:

-(x^2-2x-3)


We get rid of parentheses

x^2-x^2+2x+5x+2x+10+3=0

We add all the numbers together, and all the variables

9x+13=0

We move all terms containing x to the left, all other terms to the right

9x=-13

x=-13/9

x=-1+4/9