(x+5)(x+35)=(x+15)(x+15)

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Solution for (x+5)(x+35)=(x+15)(x+15) equation: 



(x+5)(x+35)=(x+15)(x+15)

We move all terms to the left:

(x+5)(x+35)-((x+15)(x+15))=0

We multiply parentheses ..

(+x^2+35x+5x+175)-((x+15)(x+15))=0



We calculate terms in parentheses: -((x+15)(x+15)), so:

(x+15)(x+15)

We multiply parentheses ..

(+x^2+15x+15x+225)

We get rid of parentheses

x^2+15x+15x+225

We add all the numbers together, and all the variables

x^2+30x+225

Back to the equation:

-(x^2+30x+225)



We get rid of parentheses

x^2-x^2+35x+5x-30x+175-225=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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