(x+5)(x+4)=49

Solution for (x+5)(x+4)=49 equation:

(x+5)(x+4)=49

We move all terms to the left:

(x+5)(x+4)-(49)=0

We multiply parentheses ..

(+x^2+4x+5x+20)-49=0

We get rid of parentheses

x^2+4x+5x+20-49=0

We add all the numbers together, and all the variables

x^2+9x-29=0

a = 1; b = 9; c = -29;
Δ = b2-4ac
Δ = 92-4·1·(-29)
Δ = 197
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{197}}{2*1}=\frac{-9-\sqrt{197}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{197}}{2*1}=\frac{-9+\sqrt{197}}{2}
$