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(x+5)(x+5)+25=0
We multiply parentheses ..
(+x^2+5x+5x+25)+25=0
We get rid of parentheses
x^2+5x+5x+25+25=0
We add all the numbers together, and all the variables
x^2+10x+50=0
a = 1; b = 10; c = +50;
Δ = b2-4ac
Δ = 102-4·1·50
Δ = -100
Delta is less than zero, so there is no solution for the equation
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