(x+5)(x+5)=20x

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Solution for (x+5)(x+5)=20x equation:



(x+5)(x+5)=20x
We move all terms to the left:
(x+5)(x+5)-(20x)=0
We add all the numbers together, and all the variables
-20x+(x+5)(x+5)=0
We multiply parentheses ..
(+x^2+5x+5x+25)-20x=0
We get rid of parentheses
x^2+5x+5x-20x+25=0
We add all the numbers together, and all the variables
x^2-10x+25=0
a = 1; b = -10; c = +25;
Δ = b2-4ac
Δ = -102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{10}{2}=5$

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