(x+5)(x+7)=(x-3)(x-12)

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Solution for (x+5)(x+7)=(x-3)(x-12) equation: 



(x+5)(x+7)=(x-3)(x-12)

We move all terms to the left:

(x+5)(x+7)-((x-3)(x-12))=0

We multiply parentheses ..

(+x^2+7x+5x+35)-((x-3)(x-12))=0



We calculate terms in parentheses: -((x-3)(x-12)), so:

(x-3)(x-12)

We multiply parentheses ..

(+x^2-12x-3x+36)

We get rid of parentheses

x^2-12x-3x+36

We add all the numbers together, and all the variables

x^2-15x+36

Back to the equation:

-(x^2-15x+36)



We get rid of parentheses

x^2-x^2+7x+5x+15x+35-36=0

We add all the numbers together, and all the variables

27x-1=0

We move all terms containing x to the left, all other terms to the right

27x=1

x=1/27

x=1/27

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