(x+5)(x-2)=(x+3)(x+4)

Solution for (x+5)(x-2)=(x+3)(x+4) equation:

(x+5)(x-2)=(x+3)(x+4)

We move all terms to the left:

(x+5)(x-2)-((x+3)(x+4))=0

We multiply parentheses ..

(+x^2-2x+5x-10)-((x+3)(x+4))=0


We calculate terms in parentheses: -((x+3)(x+4)), so:

(x+3)(x+4)

We multiply parentheses ..

(+x^2+4x+3x+12)

We get rid of parentheses

x^2+4x+3x+12

We add all the numbers together, and all the variables

x^2+7x+12

Back to the equation:

-(x^2+7x+12)


We get rid of parentheses

x^2-x^2-2x+5x-7x-10-12=0

We add all the numbers together, and all the variables

-4x-22=0

We move all terms containing x to the left, all other terms to the right

-4x=22

x=22/-4

x=-5+1/2