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(x+5)(x-2)=15
We move all terms to the left:
(x+5)(x-2)-(15)=0
We multiply parentheses ..
(+x^2-2x+5x-10)-15=0
We get rid of parentheses
x^2-2x+5x-10-15=0
We add all the numbers together, and all the variables
x^2+3x-25=0
a = 1; b = 3; c = -25;
Δ = b2-4ac
Δ = 32-4·1·(-25)
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{109}}{2*1}=\frac{-3-\sqrt{109}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{109}}{2*1}=\frac{-3+\sqrt{109}}{2} $
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