(x+5)(x-2)=98

Solution for (x+5)(x-2)=98 equation:

(x+5)(x-2)=98

We move all terms to the left:

(x+5)(x-2)-(98)=0

We multiply parentheses ..

(+x^2-2x+5x-10)-98=0

We get rid of parentheses

x^2-2x+5x-10-98=0

We add all the numbers together, and all the variables

x^2+3x-108=0

a = 1; b = 3; c = -108;
Δ = b2-4ac
Δ = 32-4·1·(-108)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-21}{2*1}=\frac{-24}{2}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+21}{2*1}=\frac{18}{2}
=9
$